This is for zymonrop. I made some comments about some of the answers you had Can you answer these few questions that I had. I wrote them in the document (attachedscroll down)I appreciate it if you can. Thanks Document Preview: Elementary Algebra Name Institution Affiliation Elementary Algebra Question 2 x = 3/2y +2 (Equation 1) 2x -3y = 9 (Equation 2) Substituting x in equation 2; 2(3/2y +2) -3y = 9 3y +4-3y = 9 4 =9 Therefore, because the equation has no solution, then it can be said that: (e)no solution, inconsistent system.Question 3 1/x + 1/y = 5/6 (Equation 1) 1/x- 1/y = 1/6 (Equation 2) Solution Substituting a=1/x and b=1/y then the linear equation will be a + b = 5/6 a b = 1/6 Multiplying every element with the denominator, which is 6, we will have and add the two linear equations, 6a + 6b = 5 6a- 6b = 1 12a = 6 12a/12 = 6 a = « Substituting a =1/2 using the first equation then 6(1/2) + 6b = 5 3 + 6b = 5 6b = 5-3 6b = 2 b = 1/3 Since a =1/x the value of x will be « = 1/x then multiplying both sides 2x as a common factor; «(2x) = 1/x (2x) x = 2 Also since b= 1/y, 1/3 = 1/y, then multiplying both sides by 3y as a common factor then, 1/3 (3y) = 1/y (3y) Y = 3 The value of x and y are 2 and 3 respectively. Solution c. (2, 3) Question 5 4x + 2 y +3z = 6 (Equation 1) 2x 3y 4z = -4 (Equation 2) 8x + 4y + 6z = 12 (Equation 3) Making x the subject of the equation 1, then x= 6-2y/4 -3z/4 which becomes x = 3/2-1/2y- 3z/4. Substitution for x in equation 2 then 2(3/2-1y/2-3z/4) -3y -4z = -4 3-y -3z/2-3y -4z = -4 3-4y 11z/2 = -4 Multiplying every side by 2 which is the common factor, then 8y +11z = 14 (Equation 3) Substitution for x in equation 3 then 8(3/2-1/2y- 3z/4) + 4y + 6z = 12 4y 6z + 4y + 6z = 12 8y = 12 y = 12/8 y = 3/2 The answer is b: The system is inconsistent as there are infinite solutions Question 8 [(3a2b3z-5) / 2a-3b-2z5)]-3 Solution Inversing the indices changes the power of -3 to 3. = [(2a-3b-2z5)/ (3a2b3z-5)] 3 = (8a-9b-6z15)/ (27a6b9z15) (following the law of indices on division, the powers are subtracted. = 8z30/27a15b15 Attachments: algebra.doc