Hi Ray, Please see attached file. They are the solutions to Lab6 . If you have extra time, please review them. After that, you may already submit them yourself or you can send it back to me if you found something that needs to be modified. Lab 6 document are the questions of the lab and answersand the other two are the show work requirement as required in the lab. Thanks.. Roel Document Preview: Item number 5 Formula Mass Computations (in amu) Table 2 MgO Mg = 24.305 O = 15.999 Mr = 24.305 + 15.999 = 40.304 K2S K = 39.098 S = 32.065 Mr = 2(39.098) + 32.065 = 110.26 amu C3H8O3 C = 12.011 H = 1.008 O = 15.999 Mr = 3(12.011) + 8(1.008) + 3(15.999) = 92.09 amu Ca (NO3)2 Ca = 40.078 N = 14.007 O = 15.999 Mr = 40.078 + 2[14.007 +3(15.999)] = 164.09 amu Mg3 (PO4)2 Mg = 24.305 P = 30.964 O = 15.999 Mr = 3(24.305) + 2 [30.964 + 4(15.999)] = 262.84 amu C6H2CH3 (NO2)3 C = 12.011 H = 1.008 O = 15.999 N = 14.007 Mr = 7(12.011) +5(1.008) + 3[14.007 +2(15.999)] = 227.1 amu Pt (NH3)2Cl2 Pt = 195.084 N = 14.007 H = 1.008 Cl = 35.453 Mr = 195.084 + 2[14.007+ 3(1.008)] = 300.1 amu Fe (ClO4)2 Fe = 55.845 Cl = 35.453 O = 15.999 Mr = 55.845 + 2 [35.453 + 4(15.999)] = 254.74 amu Na2CO3 10H2O Na= 22.99 C = 12.011 O = 15.999 H = 1.008 Mr = 2(22.99) + 12.011 + 3(15.999) + 10[2*1.008 + 15.999] = 286.1 amu MgSO4 7H2O Mg = 24.305 S = 32.065 O = 15.999 H = 1.008 Mr = 24.305 + 32.065 + 4(15.999) + 7 [2*1.008 + 15.999] = 246.5 amu Attachments: lab6.docxnumber_3_form.docxnumber_5_form.docx